WebMar 30, 2024 · We know that Sn = n/2 ( 2a + (n 1)d ) Where, Sn = sum of n terms of A.P. n = number of terms a = first term and d = common difference Now, Sum of first p terms = Sp = p/2 [2a + (p 1)d] Sum of first q terms = Sq = q/2 [2a + (q 1)d] It is given that Sum of first p terms = Sum of first q terms p/2 [2a + (p 1)d] = q/2 [2a + (q 1)d] p [2a + (p 1)d] = … WebResult. The results showed that HFD group had a higher body weight than LFD group after 8, 14, and 16 weeks of feeding. Furthermore, at the final observation, there were statistically significant differences between LFD group and HFD group in terms of total cholesterol (TC), triglycerides (TG), low-density lipoprotein (LDL), and high-density lipoprotein (HDL) levels.
If the p^th term of an AP is q and the q^th term is p, prove …
WebMar 30, 2024 · We know that an = a + (n 1)d Where an is nth term of AP, n is the number of terms, a be the first term & d be the common difference of the A.P. It is given that pth term is 1/ i.e. ap = 1/q a + (p 1)d = 1/q Also, qth term of A.P = 1/p i.e. aq = 1/p i.e. a + (q 1)d = 1/p Now subtracting (1) from (2) i.e. (1) (2) [a + (p 1)d] [a + (q 1)d] = 1/ 1 ... WebIf the pth term of an A.P be q and qth term be p, then its rth term will be Byju's Answer Standard XIII Mathematics If the pth te... Question If the p t h term of an A.P be q and q t h term be p, then its r t h term will be p + q + r p + q - r p + r - q p - q - r Solution The correct option is B p + q - r Explanation of the correct option. portland me carnival
The pth term of an AP is 1/q and the qth term is 1/p. Show that the …
WebIf the pth, qth, rth terms of an AP be x, y, z respectively, show that x(q – r) + y(r – p) + z(p – q). Q13. If the pth term of an AP is 1/q and the qth term is 1/p, show that the sum of pq terms is ½(pq + 1). LONG ANSWER TYPE QUESTIONS Q14. In an AP of 50 terms, the sum of first 10 terms is 210 and sum of its last 15 terms is 2565. WebMar 30, 2024 · Transcript. Example 21 If pth, qth, rth and sth terms of an A.P. are in G.P, then show that (p – q), (q – r), (r – s) are also in G.P. We know that the nth term of AP is a + (n – 1)d i.e. an = a + (n – 1)d It is given that ap, aq, ar & as in GP i.e. their common ratio is same So,𝑎_𝑞/𝑎_𝑝 = (ar )/qq = 𝑎𝑠/𝑎𝑟 We need to show (p – q), (q – r), (r – s) are in ... WebIn an A.P, if the p th term is 1/q and q th term is 1/p, prove that the sum of first pq terms is 1/2 (pq + 1), where p ≠ q. Solution: It is known that general term of an A.P is a n = a + (n - 1) d p th term = a n = a + (n - 1) d = 1/q .... (1) q th term = a n = a + (n - 1) d = 1/p .... (2) Subtracting (2) from (1) , we obtain optima digital battery charger